A) \[\frac{5}{12}\]
B) \[\frac{7}{12}\]
C) \[\frac{1}{12}\]
D) None of these
Correct Answer: C
Solution :
| [c] Total no. of sample outcomes \[=6\times 6=36\] |
| Favourable outcomes |
| \[\{(4,6),(5,5),(6,4)\}\] |
| \[\therefore \] Total no. of favourable outcomes =3 |
| So. required probability \[=\frac{3}{36}=\frac{1}{12}.\] |
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