A) \[\frac{1}{5}\]
B) \[\frac{6}{25}\]
C) \[\frac{1}{4}\]
D) \[\frac{13}{50}\]
Correct Answer: C
Solution :
| [c] Total number of outcomes = 100 |
| The prime numbers from 1 to 100 are: |
| \[\{2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,\]\[59,61,67,71,73,79,83,89,97\}.\] |
| So. favourable number of outcomes = 25 |
| \[\therefore \] Required probability \[=\frac{25}{100}=\frac{1}{4}\] |
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