A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
Smallest composite number \[=4=2\times 2={{2}^{2}}\] |
and smallest prime number \[=2={{2}^{1}}\] |
\[\therefore \,\,\,HCF\left( 4,2 \right)={{2}^{1}}=2\] |
[since, HCF is the product of the smallest power of each common prime factor involved in the numbers] |
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