A) an integer
B) a rational number
C) an irrational number
D) None of these
Correct Answer: C
Solution :
Sol. [c] We have, \[\sqrt{12}=\sqrt{4\times 3}=2\sqrt{3}.\] |
Here, 2 is rational and \[\sqrt{3}\] is irrational. |
And, the product of a rational and an irrational is irrational. |
\[\therefore \,2\sqrt{3}\]i.e., \[\sqrt{12}\] is an irrational number. |
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