| In Figure, assuming the diodes to be ideal, |
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A) \[{{\operatorname{D}}_{1}}\] is forward biased and \[{{\operatorname{D}}_{2}}\] is reverse biased and hence current flows from A to B
B) \[{{\operatorname{D}}_{2}}\] is forward biased and \[{{\operatorname{D}}_{1}}\] is reverse biased and hence no current flows from B to A and vice versa.
C) \[{{\operatorname{D}}_{1}}\] and \[{{\operatorname{D}}_{2}}\] are both forward biased and hence current flows from A to B.
D) \[{{\operatorname{D}}_{1}}\] and \[{{\operatorname{D}}_{2}}\] are both reverse biased and hence no current flows from A to B and vice versa.
Correct Answer: B
Solution :
Option [b] is correct Explanation: In circuit, A is at -10 V and B is at 0 V. So B is positive than A. So\[{{\operatorname{D}}_{2}}\] is in forward bias and \[{{\operatorname{D}}_{1}}\] is in reverse bias, so no current flows from A to B or B to A.
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