A) penta, n
B) tri, p
C) penta, p
D) both [a] and [b]
Correct Answer: D
Solution :
Option [d] is correct. |
Explanation: When a semiconductor having 4 valence electrons is doped with an element having 3 valence electrons, then an excess hole is generated and the semiconductor becomes p-type extrinsic semiconductor. |
When a semiconductor having 4 valence electrons is doped with an element having 5 valence electrons, then an excess electron becomes available and the semiconductor becomes n-type extrinsic semiconductor. |
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