A) \[HN{{O}_{3}}\] (68%) + \[{{H}_{2}}O\] (32%): Maximum boiling azeotrope, boiling point = 393.5 K
B) \[{{H}_{2}}O\] (43%) + HI (57%) : Minimum boiling azeotrope, boiling point = 290 K
C) \[{{C}_{2}}{{H}_{5}}OH\](95.5%) + \[{{H}_{2}}O\] (4.5%): Minimum boiling azeotrope, boiling point = 351.15 K
D) Chloroform (93.2%) + \[{{C}_{2}}{{H}_{5}}OH\] (6.8%) : Minimum boiling azeotrope, boiling point = 332.3 K.
Correct Answer: B
Solution :
\[{{H}_{2}}O\] (43%) and Hl (57%) make maximum boiling azeotropic mixture on boiling at 400 K.
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