12th Class Chemistry Solutions / विलयन Question Bank MCQs - Solutions

  • question_answer
    Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on dissolving 1 g of Y in 20 g of liquid X. If molar mass of X is 200, what is the molar mass of Y?

    A) 20

    B) 50

    C) 100

    D) 200

    Correct Answer: A

    Solution :

    \[\frac{P_{A}^{{}^\circ }-{{P}_{A}}}{P_{A}^{{}^\circ }}=\frac{{{n}_{B}}}{{{n}_{A}}}\] \[\frac{2-1}{2}=\frac{{{W}_{B}}}{{{M}_{B}}}\times \frac{{{M}_{A}}}{{{W}_{A}}}\Rightarrow \frac{1}{2}=\frac{1}{{{M}_{B}}}\times \frac{200}{20}\] \[\Rightarrow {{M}_{B}}=\frac{200\times 2}{20}=20\]


You need to login to perform this action.
You will be redirected in 3 sec spinner