A) Solution having 15.4 mg \[N{{a}^{+}}/mL\]
B) Solution having 2.07 g NaCl/100 mL
C) \[0.208M\text{ }N{{a}_{2}}S{{O}_{4}}\]
D) All of these have equal concentration of \[N{{a}^{+}}\]
Correct Answer: A
Solution :
[a]| (a) \[15.4\,\,mg\,\,N{{a}^{+}}=15.4\times {{10}^{-3}}g\,\,N{{a}^{+}}m{{L}^{-1}}\] |
| \[=15.4g\,\,N{{a}^{+}}\,{{L}^{-1}}=\frac{15.4}{23}mol\,\,N{{a}^{+}}\,{{L}^{-1}}\] |
| \[\therefore \] \[[N{{a}^{+}}]=\frac{15.4}{23}=0.669\,\,M\] |
| (b) \[2.07g\,\,NaCl/100\,mL=20.7g\,\,NaCl/L\] |
| \[=\frac{20.7}{58.5}=mol\,\,{{L}^{-1}}=0.353\,\,M\] |
| \[[N{{a}^{+}}]=0.353\,\,M\] |
| (c) \[N{{a}_{2}}S{{O}_{4}}\rightleftharpoons \,2N{{a}^{+}}+SO_{4}^{2\,-}\] |
| \[\therefore \] \[[N{{a}^{+}}]=0.208\times 2=0.416\,\,M\] |
| Thus, (a) has the highest molar concentration of \[N{{a}^{+}}.\] |
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