A) 84.72%
B) 15.28%
C) 50%
D) 44%
Correct Answer: A
Solution :
Mass of solution = Mass of \[{{C}_{6}}{{H}_{6}}\] + Mass of\[CC{{l}_{4}}\] \[=22+\text{ }122=\text{ }144\text{ }g\] Mass % of \[CC{{l}_{4}}\] = \[\frac{122}{144}\times \] 100 =84.72%You need to login to perform this action.
You will be redirected in
3 sec