A) 80 torr
B) 140 torr
C) 72 torr
D) 70 torr
Correct Answer: C
Solution :
Mole fraction of \[P=\frac{3}{3+2}=0.6\] Mole fraction of \[Q=\frac{2}{3+2}=0.4\] \[{{P}_{total}}={{P}_{p}}+{{P}_{Q}}=P_{p}^{{}^\circ }{{x}_{P}}+P_{Q}^{{}^\circ }{{x}_{Q}}\] \[=\text{ }80~\times \,0.6\text{ }+\text{ }60~\times \,0.4\text{ }=\text{ }72\text{ }torr\]
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