A) \[6\text{ }g\text{ }mo{{l}^{-1}}\]
B) \[60\text{ }g\text{ }mo{{l}^{-1}}\]
C) \[36\text{ }g\text{ }mo{{l}^{-1}}\]
D) \[32\text{ }g\text{ }mo{{l}^{-1}}\]
Correct Answer: C
Solution :
No. of moles of urea =\[\frac{10}{60}=\frac{1}{6}\] Weight of solute, X = 6 g No. of moles of X = \[\frac{6}{M}\] For isotonic solutions, \[{{n}_{1}}={{n}_{2}}\] or\[\frac{1}{6}=\frac{6}{M}\]or \[M=36g\text{ }mo{{l}^{-1}}\]
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