A) \[NO\,\,;\,\,N{{O}_{2}}\,\,\,;\,\,HN{{O}_{3}}\]
B) \[N{{O}_{2}}\,\,;\,\,NO\,\,;\,\,HN{{O}_{3}}\]
C) \[{{N}_{2}}O\,\,;\,\,NO\,\,;\,\,HN{{O}_{2}}\]
D) \[NO\,\,\,;\,\,{{N}_{2}}O\,\,;\,\,HN{{O}_{3}}\]
Correct Answer: A
Solution :
\[3Cu+8HN{{O}_{3}}(dil.)\to 3Cu{{(N{{O}_{3}})}_{2}}+\underset{(X)}{\mathop{2NO}}\,+4{{H}_{2}}O\] \[2NO+{{O}_{2}}\to \underset{(Y)}{\mathop{2N{{O}_{2}}}}\,\] \[3N{{O}_{2}}+{{H}_{2}}O\to \underset{(Z)}{\mathop{2HN{{O}_{3}}}}\,+\underset{(X)}{\mathop{NO}}\,\]You need to login to perform this action.
You will be redirected in
3 sec