A) \[{{N}_{3}}H\]
B) \[N{{H}_{3}}\]
C) \[N{{H}_{2}}OH\]
D) \[{{N}_{2}}{{H}_{4}}\]
Correct Answer: A
Solution :
O.S. of N in \[{{N}_{3}}H=-\,\,\frac{1}{3}\] |
O.S. of N in \[N{{H}_{3}}\] = - 3 |
O.S. of N in \[N{{H}_{2}}OH\] = - 1 |
O.S. of N in \[{{N}_{2}}{{H}_{4}}\] = - 2 |
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