A) oxygen atom has the tendency to form multiple \[p\pi -p\pi \] bonds
B) S - S bond is not as stable as S = S bond
C) O - O chains are less stable than S - S chains
D) oxygen is paramagnetic while sulphur is diamagnetic.
Correct Answer: A
Solution :
Oxygen atom can form multiple \[p\pi -p\pi \] bonds with other oxygen atom on account of small size while S=S is not so stable as compared to -S-S-S- chains. Hence S exists as S8 while O exists as \[{{O}_{2}}\].You need to login to perform this action.
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