A) \[{{H}_{2}}Se<{{H}_{2}}Te<{{H}_{2}}Po<{{H}_{2}}O<{{H}_{2}}S\]
B) \[{{H}_{2}}S<{{H}_{2}}O<{{H}_{2}}Se<{{H}_{2}}Te<{{H}_{2}}Po\]
C) \[{{H}_{2}}O<{{H}_{2}}S<{{H}_{2}}Se<{{H}_{2}}Te<{{H}_{2}}Po\]
D) \[{{H}_{2}}Po<{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}S<{{H}_{2}}O\]
Correct Answer: D
Solution :
The thermal stability of hydrides decreases from \[{{H}_{2}}O\] to \[{{H}_{2}}Po\]. This is because as the size of atom E in \[{{H}_{2}}E\] increases, the bond H-E becomes weaker and thus breaks on heating. Therefore, the correct order of thermal stability is \[{{H}_{2}}Po<{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}S<{{H}_{2}}O\].You need to login to perform this action.
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