| Complete the following reactions by filling the appropriate choice. |
| [A] \[6Xe{{F}_{4}}\,\,+\,\,12{{H}_{2}}O\,\,\to \,\,4Xe\,\,+\,\,2Xe{{O}_{3}}\,\,+\underline{\,\,(i)}\,\,+\,\,\underline{(ii)}\] |
| [B] \[Xe{{F}_{6}}+3{{H}_{2}}O\to \underline{(iii)}+6HF\] |
A)
(i)
(ii)
(iii)
\[{{F}_{2}}\]
\[{{H}_{2}}O\]
\[XeO{{F}_{4}}\]
B)
(i)
(ii)
(iii)
24HF
\[3{{O}_{2}}\]
\[Xe{{O}_{3}}\]
C)
(i)
(ii)
(iii)
2HF
\[2{{H}_{2}}O\]
XeO
D)
(i)
(ii)
(iii)
HF
\[{{H}_{2}}O\]
\[X{{e}_{2}}{{O}_{3}}\]
Correct Answer: B
Solution :
\[6Xe{{F}_{4}}+12{{H}_{2}}O\to 4Xe+2Xe{{O}_{3}}+\underset{(i)}{\mathop{24HF}}\,+\underset{(ii)}{\mathop{3{{O}_{2}}}}\,\] \[Xe{{F}_{_{6}}}+3{{H}_{2}}O\to \underset{\left( iii \right)}{\mathop{Xe{{O}_{3}}}}\,+6HF\]
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