12th Class Chemistry The Solid State / ठोस प्रावस्था Question Bank MCQs - The Solid State

  • question_answer
    Match the column I with column II and mark the appropriate choice.
    Column I  (Structure) Column II (Packing efficiency)
    [A] Simple cubic structure (i) 68%
    [B] Face centred cubic structure (ii) 74%
    [C] Body centred cubic structure (iii) 52%

    A) [A] \[\to \] (iii), [B] \[\to \] (ii), [C] \[\to \] (i)

    B) [A] \[\to \] (i), [B] \[\to \] (ii), [C] \[\to \] (iii)

    C) [A] \[\to \] (ii), [B] \[\to \] (i), [C] \[\to \] (iii)

    D) [A] \[\to \] (iii), [B] \[\to \] (i), [C] \[\to \] (ii)

    Correct Answer: A

    Solution :

    For simplexubic structure,
    \[V={{a}^{3}}\](volume of the unit cell)
    \[V=\frac{4}{3}\pi {{r}^{3}}\] (volume of one atom)
    \[=\frac{4}{3}\pi {{\left( \frac{a}{2} \right)}^{3}}=\frac{\pi {{a}^{3}}}{6}\]
    Packing efficiency \[=\frac{V'}{V}=\frac{\pi {{a}^{3}}/6}{{{a}^{3}}}=\frac{\pi }{6}=0.52\] = 0.52 or 52%
    For fcc structure,
    \[{{V}^{'}}=4\times \frac{4}{3}\pi {{r}^{3}}\](4 atoms per unit cell)
    \[r=\frac{a}{2\sqrt{2}}\]
    \[V'=\frac{16}{3}\pi {{\left( \frac{a}{2\sqrt{2}} \right)}^{3}}=\frac{\pi }{3\sqrt{2}}{{a}^{3}}\]
    Volume of unit cell \[=V={{a}^{3}}\]
    Packing efficiency
    \[=\frac{V'}{V}=\frac{\pi {{a}^{3}}}{3\sqrt{2}{{a}^{3}}}=\frac{\pi }{3\sqrt{2}}=0.74\] or 74%
    For bee structure,
    \[V'=2\times \frac{4}{3}\pi {{r}^{3}}\] (2 atoms per unit cell)
    \[r=\frac{\sqrt{3}}{4}a\]
    \[V'=2\times \frac{4}{3}\pi {{\left( \frac{\sqrt{3}}{4}a \right)}^{3}}=\frac{\sqrt{3}\pi {{a}^{3}}}{8}\]
    \[V={{a}^{3}}\]
    Packing efficiency
    \[=\frac{V'}{V}=\frac{\sqrt{3}\pi {{a}^{3}}}{8{{a}^{3}}}=\frac{\sqrt{3}}{8}\pi =0.68\] or 68%


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