A) \[7:9\]
B) \[9:81\]
C) \[9:7\]
D) \[81:7\]
Correct Answer: C
Solution :
[c] Given, area of two similar triangles, |
\[{{A}_{1}}=81\,c{{m}^{2}}\] |
\[{{A}_{2}}=49\,c{{m}^{2}}\] |
Ratio of corresponding medians |
\[=\sqrt{\frac{{{A}_{1}}}{{{A}_{2}}}}=\sqrt{\frac{81}{49}}=\frac{9}{7}\] |
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