A) \[28\]
B) \[14\sqrt{2}\]
C) \[21\]
D) \[49\]
Correct Answer: D
Solution :
[d] Let ABCD be the square with side length x cm. |
In \[\Delta ABC,\] by Pythagoras theorem, |
\[A{{C}^{2}}=B{{C}^{2}}+A{{B}^{2}}\] |
\[\Rightarrow \,\,\,{{(7\sqrt{2})}^{2}}={{x}^{2}}+{{x}^{2}}\] (Given, \[AC=7\sqrt{2}\,cm\]) |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,49\times 2=2{{x}^{2}}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,{{x}^{2}}=49\] |
\[\therefore \] Area of square \[={{x}^{2}}=49c{{m}^{2}}\] |
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