A) 5 m
B) 6 m
C) 7 m
D) 8 m
Correct Answer: C
Solution :
[c] Let AB be the ladder and CA be the building in which C is the base of the building. |
Also, \[AB=25\,m\] |
and \[CA=24\,cm\] |
Now, in right \[\Delta ACB,\] |
\[A{{B}^{2}}=B{{C}^{2}}+A{{C}^{2}}\] |
(By Pythagoras theorem) |
\[\Rightarrow \,\,\,\,\,\,B{{C}^{2}}=A{{B}^{2}}-A{{C}^{2}}\] |
\[={{(25)}^{2}}-{{(24)}^{2}}\] |
\[=(25-24)\,(25+24)=49\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,BC=7\,m\] |
So, the distance of the foot of the ladder from the base of the building is\[7\,m\]. |
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