A) \[120{}^\circ \]
B) \[60{}^\circ \]
C) \[90{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: C
Solution :
[c] \[A{{C}^{2}}=144\,c{{m}^{2}},\] |
\[A{{B}^{2}}=108\,c{{m}^{2}}\] |
\[B{{C}^{2}}=36\,c{{m}^{2}}\] |
Now \[A{{B}^{2}}+B{{C}^{2}}=144=A{{C}^{2}}\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\angle B=90{}^\circ \] |
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