A) 100m
B) 120m
C) 25m
D) 200m
Correct Answer: A
Solution :
Let the height of the tower be x. As \[\angle B=\angle E=90{}^\circ\]and angle of elevation of sun is same. |
In \[\Delta ABC\]and \[\Delta DEF\] |
\[\angle B=\angle E\] [right angle] |
\[\angle C=\angle F\] [angle of elevation] |
\[\Delta ABC\tilde{\ }\Delta DEF\] [from AA similarity] |
\[\therefore \,\,\,\,\frac{AB}{DE}=\frac{BC}{EF}\Rightarrow \,\frac{20}{x}=\frac{10}{50}\] |
\[\Rightarrow \,\,\,\,\,x=\frac{20\times 50}{10}=100\,m\] |
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