10th Class Mathematics Triangles Question Bank MCQs - Triangles

  • question_answer
    In the given figure, \[\text{AD}=\text{1}.\text{28 cm},\]\[\text{DB}=\text{2}\text{.56 cm},\] \[\text{AE}=0.\text{64 cm}\]. DE will be parallel to BC, if EC =      

    A) \[\text{1}.\text{28 cm}\]

    B) \[\text{2}\text{.56 cm}\]

    C) \[0.\text{64 cm}\]

    D) \[0.\text{32 cm}\]

    Correct Answer: A

    Solution :

    [a] \[DE||BC,\] if \[\frac{AD}{DB}=\frac{AE}{BC}\]
    \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\frac{1.28}{2.56}=\frac{0.64}{EC}\,\,\,\,\,\,\Rightarrow \,\,EC=1.28\,cm\]


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