A) \[2\,cm\]
B) \[1.2\,cm\]
C) \[1.5\,cm\]
D) \[4\,cm\]
Correct Answer: C
Solution :
[c] In \[\Delta ABC,\] \[DE||BC\] |
\[\therefore \,\,\,\,\,\,\frac{AB}{AD}=\frac{AC}{AE}\] (By Thales theorem) |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\frac{6}{AD}=\frac{AC}{\frac{1}{4}AC}\,\,\,\,\,\,\,\,\left[ AE=\frac{1}{4}AC\,\,(given) \right]\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,AD=\frac{6}{4}=1.5\,\,cm\] |
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