In given figure \[AD=3cm,\] \[AE=5cm,\] \[BD=4cm,\] \[CE=4cm,\] \[CF=2cm,\] \[BF=2.5cm,\] then: |
A) \[DE\left\| BC \right.\]
B) \[DF\left\| AC \right.\]
C) \[EF\left\| AB \right.\]
D) None of the above
Correct Answer: C
Solution :
[c] \[\frac{CF}{FB}=\frac{CE}{AE}\] |
\[\therefore \,\,\,\,\,\,\,\,\,EF||AB\] |
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