| In a \[\Delta ABC,\] it is given that \[AB=6cm,\] \[\text{AC}=\text{8 cm}\] and \[\text{AD}\] is the bisector of \[\angle A\]. |
| Then, \[BD:DC=\] |
 |
A) \[3:4\]
B) \[9:16\]
C) \[4:3\]
D) \[\sqrt{3}:2\]
Correct Answer: A
Solution :
[a] We know that the bisector of an angle of a triangle divides the opposite side in the ratio of the sides containing the angle. \[\therefore \,\,\,\,\,\,\,\,\,\,\,BD:DC=AB:AC=6:8=3:4\]
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