| In right triangles \[ABC,\] \[BC=a,\] \[AC=b,\]\[AB=c,\] \[CD\bot AB.\] If area of \[\Delta ABC=A,\] then \[CD=\] |
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A) \[\frac{2A}{C}\]
B) \[\frac{A}{C}\]
C) \[\frac{A}{2C}\]
D) \[\frac{C}{A}\]
Correct Answer: A
Solution :
| [a] Area of \[\Delta ABC,\] \[(A)=\frac{1}{2}AB\times CD\] |
| \[\Rightarrow \,\,A=\frac{1}{2}\times C\times CD\,\,\,\,\,\,\,\,\Rightarrow \,\,CD=\frac{2}{C}A\] (A = Area) |
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