A) will be double.
B) will be half.
C) will remain same.
D) will be four times.
Correct Answer: D
Solution :
| Option [d] is correct. |
| Explanation: Fringe width = \[\beta =\lambda \operatorname{D}/\,d\] |
| Initially, \[\beta =\lambda \operatorname{D}/\,d\] |
| Finally, \[\beta '=\frac{\lambda \times 2\operatorname{D}}{d/2}=4\times \frac{\lambda \operatorname{D}}{d}=4\beta \] |
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