A) \[\frac{1}{5}\]
B) \[\frac{15}{4}\]
C) 4
D) 8
Correct Answer: B
Solution :
\[\frac{{{x}_{1}}+{{x}_{2}}+.....+{{x}_{10}}}{10}=4.5\] Þ \[{{x}_{1}}+{{x}_{2}}+.....+{{x}_{10}}=45\] and \[\frac{{{x}_{11}}+{{x}_{12}}+.....+{{x}_{40}}}{30}=3.5\] Þ \[{{x}_{11}}+{{x}_{12}}+.....+{{x}_{40}}=105\] \\[{{x}_{1}}+{{x}_{2}}+.....+{{x}_{40}}=150\] \ \[\frac{{{x}_{1}}+{{x}_{2}}+.....+{{x}_{40}}}{40}=\frac{150}{40}\]\[=\frac{15}{4}\].
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