A) \[{{3}^{2/n}}\]
B) \[{{3}^{(n-1)/2}}\]
C) \[{{3}^{n/2}}\]
D) \[{{3}^{(n+1)/2}}\]
Correct Answer: D
Solution :
G.M.\[={{({{3.3}^{2}}{{.3}^{3}}{{.......3}^{n}})}^{1/n}}\] \[={{({{3}^{1+2+.......n}})}^{1/n}}\]\[={{\left( {{3}^{\frac{n\,(n+1)}{2}}} \right)}^{1/n}}\]\[={{3}^{\frac{n+1}{2}}}\].
You need to login to perform this action.
You will be redirected in
3 sec
