• question_answer Naveen added $\text{46 }ml$ of syrup to $\text{1}\text{.09 }l$ of water. What is the capacity of the vessel needed to hold the complete mixture? A)  $\text{1}.\text{55 }l$                         B)  $\text{1}.0\text{9 }l$ C)  $\text{1}.0\text{44 }l\text{ }$          D)    $\text{1}.\text{136 }l$

Quantity of syrup 46 m Quantity of water $=1.09l=1090ml$ $\therefore$ The capacity of the vessel that can hold the mixture $=\text{ 1}0\text{9}0\text{ }ml\text{ }+\text{ 46 }ml$       $=\text{1136 }ml=\text{1}.\text{136 }l$