A) \[a\le \text{Var}(x)\le b\]
B) \[{{a}^{2}}\le \text{Var}(x)\le {{b}^{2}}\]
C) \[\frac{{{a}^{2}}}{4}\le \text{Var}(x)\]
D) \[{{(b-a)}^{2}}\ge \text{Var}(x)\]
Correct Answer: D
Solution :
Since S.D. \[\le \] Range = b ? a \ Var \[(x)\le {{(b-a)}^{2}}\] or \[{{(b-a)}^{2}}\ge \]Var (x).You need to login to perform this action.
You will be redirected in
3 sec