| Size of items | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Frequency | 2 | 4 | 5 | 8 | 7 | 3 | 2 |
A) \[\left( \frac{31+1}{4} \right)\]th item
B) \[\left[ 2\left( \frac{31+1}{4} \right) \right]\]th item
C) \[\left[ 3\left( \frac{31+1}{4} \right) \right]\]th item
D) \[\left[ 4\left( \frac{31+1}{4} \right) \right]\]th item
Correct Answer: C
Solution :
Upper Quartile = Size of \[{{\left[ 3\frac{(n+1)}{4} \right]}^{th}}\]item = Size of \[{{\left[ 3\left( \frac{31+1}{4} \right) \right]}^{th}}\]item, \[[\because \Sigma f=31]\].
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