A) 4 m
B) 16m
C) 12m
D) cannot be determined
Correct Answer: C
Solution :
Let the length and the breadth of the field be x and y respectively in metres. \[AC=\sqrt{{{x}^{2}}+{{y}^{2}}}\,\,\,\,\Rightarrow \,\,\,\sqrt{{{16}^{2}}+{{y}^{2}}}=20\] \[\Rightarrow \,\,y=12\,m\].You need to login to perform this action.
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