A) \[4\frac{1}{15}c{{m}^{2}}\]
B) \[5\frac{5}{14}c{{m}^{2}}\]
C) \[16\frac{2}{8}c{{m}^{2}}\]
D) \[15\,\,c{{m}^{2}}\]
Correct Answer: B
Solution :
\[\Rightarrow \]\[2r=5\,\,cm\] \[\therefore \]\[r=\frac{5}{2}cm\] Area \[=\pi {{r}^{2}}=\pi \times {{r}^{2}}=\pi \times {{\left( \frac{5}{2} \right)}^{2}}=\frac{25\pi }{4}\] Area of Square\[={{(5\,\,cm)}^{2}}=25\,\,c{{m}^{2}}\] \[\therefore \]Area of Shaded region \[=25=\frac{25\pi }{4}=25\left( 1-\frac{22}{7\times 4} \right)\] \[=25\times \frac{6}{7\times 4}=\frac{75}{14}=5\frac{5}{14}c{{m}^{2}}\]
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