A) \[20%\]measure
B) \[4%\]decrease
C) \[20%\]decrease
D) \[4%\]increase
Correct Answer: B
Solution :
\[\left. \begin{align} & 1\to 1\times \left( 1+\frac{60}{100} \right)=1.61 \\ & b\to b\times \left( 1-\frac{40}{100} \right)=0.6\,b \\ \end{align} \right\}\]old area \[l\times b,\]new area\[=1.61\times 0.6b=(0.96)lb\] \[\therefore \]Percentage decrease \[=lb-0.96\text{ }Ib=0.04=4%\]You need to login to perform this action.
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