A) \[140{}^\circ \]
B) \[135{}^\circ \]
C) \[150{}^\circ ~\]
D) \[160{}^\circ \]
Correct Answer: C
Solution :
| [c] Given, Interior angle of the first polygon \[=120{}^\circ \] Let number of sides in first polygon be \[{{n}_{1}}.\] Then, \[\frac{{{n}_{1}}-2}{{{n}_{1}}}\times 180{}^\circ =120{}^\circ \] \[\Rightarrow \] \[3\,{{n}_{1}}-6=2{{n}_{1}}\] \[\Rightarrow \] \[{{n}_{1}}=6\] Sides of the second polygon \[=6\times 2=12\] Interior angle of the second polygon \[=\frac{12-2}{12}\times 180{}^\circ =150{}^\circ \] |
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