A) 500
B) 600
C) 700
D) 800
Correct Answer: A
Solution :
[a] \[\because \]\[d=98\,cm\] \[\therefore \]Circumference of wheel \[=\pi \,d\] \[=\frac{22}{7}\times 98=308\,cm\] Hence, number of revolutions \[=\frac{\text{Distance}}{\text{Cicumference}\,\text{of}\,\text{wheel}}\] \[=\frac{1540\times 100}{308}=500\] |
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