A) 2 : 1
B) 1 : 2
C) \[\sqrt{2}:1\]
D) \[1:\sqrt{2}\]
Correct Answer: A
Solution :
[a] Ratio of the areas of the circumcircle and incircle of a square \[=\frac{\pi \,{{(Diagonal)}^{2}}}{\pi \,{{(Side)}^{2}}}\] \[=\frac{{{(Side\times \sqrt{2})}^{2}}}{{{(Side)}^{2}}}=\frac{2}{1}\] \[=2:1\] |
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