A) \[72\text{ }c{{m}^{2}}\]
B) \[42\,c{{m}^{2}}\]
C) \[26\,c{{m}^{2}}\]
D) \[21\,c{{m}^{2}}\]
Correct Answer: D
Solution :
[d] \[\angle \,AOB=\angle COD\] \[\angle \,CAB=\angle \,DCA\] \[\angle \,DBA=\angle \,CDB\] \[\Delta \,AOB\] is similar to \[\Delta \,COD\,\frac{AB}{CD}\] \[\Rightarrow \]\[\frac{\text{Area}\,\text{of}\,\Delta \,AOB}{\text{Area}\,\text{of}\,\Delta COD}={{\left( \frac{2}{1} \right)}^{2}}\] Area of \[\Delta \,COD=84\times \frac{1}{4}=21\,c{{m}^{2}}\] |
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