A) 3
B) 5
C) 6
D) 8
Correct Answer: B
Solution :
[b] Given, \[\frac{(2n-4)}{n}\times 90{}^\circ =\frac{3}{5}\times 180{}^\circ \] \[\Rightarrow \] \[\frac{(2n-4)}{n}=\frac{3}{5}\times 2\] \[\Rightarrow \] \[\frac{n-2}{n}=\frac{3}{5}\] \[\Rightarrow \] \[5n-10=3n\] \[\Rightarrow \] \[2n=10\] \[\Rightarrow \] \[n=5\] Thus, the polygon has 5 sides. |
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