A) 512
B) 2055
C) 2058
D) 2085
Correct Answer: A
Solution :
[a] Volume of the sphere \[=\left( \frac{4}{3}\pi \times 8\times 8\times 8 \right)c{{m}^{3}}\] Volume of each lead ball \[=\frac{4}{3}\pi \times 1\times 1\times 1=\frac{4\pi }{3}c{{m}^{3}}\] \[\therefore \]Number of lead balls \[=\frac{4}{3}\pi \times 8\times 8\times 8\times \frac{3}{4\pi }\] \[=8\times 8\times 8=512\] |
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