A) 1
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
[d] Given diameter of the water drop\[=\frac{1}{10}\,cm\] Hence radius of the water drop \[=\frac{\text{Diameter}\,\text{of}\,\text{water}\,\text{drop}}{2}\] \[=\frac{1}{2}\times \frac{1}{10}\,cm=\frac{1}{20}\,cm\] Let radius of rim of the glass \[=r\] Hence, height the glass \[=2r\] According to question. \[32000\times \frac{4}{3}\pi \times \frac{1}{20}\times \frac{1}{20}\times \frac{1}{20}\] \[{{r}^{3}}=\frac{32000\times 4}{20\times 20\times 20\times 2}\] \[{{r}^{3}}=8\]\[\Rightarrow \]\[r=2\] \[\therefore \]Height of the glass \[=2r=2\times 2=4\,cm\] |
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