A) 8 cm
B) 6 cm
C) 10 cm
D) 12 cm
Correct Answer: C
Solution :
[c] \[{{d}_{1}}=12\,cm\] \[{{d}_{2}}=16\,cm\] \[\therefore \] \[OA=\frac{1}{2}{{d}_{1}}=6\,cm\] and \[OB=\frac{1}{2}{{d}_{2}}=8\,cm\] Now, in \[\Delta AOB,\] \[A{{B}^{2}}=O{{A}^{2}}+O{{B}^{2}}\] \[=36+64=140\] \[\Rightarrow \] \[AB=10\,cm\] |
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