| Base of a right pyramid is a square of side 10 cm. |
| If the height of the pyramid is 12 cm, then its total surface area is [SSC CGL Tier n, 2015] |
A) \[260\text{ }c{{m}^{2}}\]
B) \[400\,c{{m}^{2}}\]
C) \[360\,c{{m}^{2}}\]
D) \[460\text{ }c{{m}^{2}}\]
Correct Answer: C
Solution :
| [c] Slant height of a right pyramid \[=\sqrt{{{\left( \frac{10}{2} \right)}^{2}}+{{(12)}^{2}}}\] \[=\sqrt{{{(5)}^{2}}+144}=\sqrt{25+144}\] \[=\sqrt{169}=13\,cm\] |
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