A) 20% measure
B) 4% decrease
C) 20 % decrease
D) 4% increase
Correct Answer: B
Solution :
\[\left. \begin{align} & 1\to 1\times \left( 1+\frac{60}{100} \right)=1.61 \\ & b\to b\times \left( 1-\frac{40}{100} \right)=0.6b \\ \end{align} \right\}\]old area \[=l\times b,\]new area\[=1.61\times 0.6\,b=(0.96)\,1b\] \[\therefore \]Percentage decrease \[=1b-0.96Ib=0.04=4%\]You need to login to perform this action.
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