A) \[\sqrt{3}:1\]
B) \[\sqrt{2}:1\]
C) \[\sqrt{5}:2\]
D) \[2:\sqrt{5}\]
Correct Answer: A
Solution :
As shown in figure, ADE is a triangle. \[s=\frac{a+b+c}{2}.\] \[\frac{\sqrt{3}}{2}{{(side)}^{2}}.\] or \[=\sqrt{3}\] By symmetry, FC = 6 cm. Let AB=x Then, \[\Delta ABC=\frac{1}{2}\times base\times height=\frac{1}{2}\times BC\times AD\] or \[\Delta ABC\] or \[\Delta ABC=\frac{1}{2}\times BC\times AB\]. \[ABCD=AB\times BC=l\times b\] Area of trapezium\[=l+b+l+b\]You need to login to perform this action.
You will be redirected in
3 sec