8th Class
Mathematics
Mensuration
Question Bank
Mensuration
question_answer
A tent is in the form of a right circular cylinder surmounted by a cone. The diameter of cylinder is 24 m, the height of the cylindrical portion is 11 m, while the vertex of the cone is 16 m above the ground. The area of the canvas required for the tent is:
A) \[\Rightarrow \]
B) \[\frac{r}{21-r}=\frac{4}{3}\]
C) \[\Rightarrow \]
D) \[3r=84-4r\]
Correct Answer:
A
Solution :
\[24\sqrt{35}c{{m}^{2}}\] \[150c{{m}^{2}}\] \[30\sqrt{7}cm\] Area of the canvas = lateral surface area of cylinder + lateral surface area of cone \[\frac{15\sqrt{7}}{2}cm\] \[\frac{15\sqrt{7}}{4}cm\]