A) 2 : 3
B) 1 : 1
C) 2 : 1
D) 1 : 2
Correct Answer: C
Solution :
Let the height and radius of the ends of a cylinder be h and r respectively. Now Curved surface \[=2\times \] Area of the ends \[2\pi rh=2\times (\pi \,{{r}^{2}}+\pi \,{{r}^{2}})\] \[\therefore \] \[\frac{h}{r}=\frac{2}{1}\] or \[h:r\,\,::\,\,2:1\]You need to login to perform this action.
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